This paper considered the efficiency of transformation of renewable energy into electricity when hydrogen is used as an energy carrier: electrolysis – hydrogen compression and transportation – hydrogen utilization as a fuel in a combined cycle power plant.
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This paper considered the efficiency of transformation of renewable energy into electricity when hydrogen is used as an energy carrier: electrolysis – hydrogen compression
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Efficiency of hydrogen utilization as a fuel for power generation is up to 60%. Energy efficiency of system “green hydrogen production, compression, and utilization as a fuel” is about 40%. This work is focused on analyzing the efficiency of using “green” hydrogen as a fuel for power generation systems.
Therefore, in further analysis, the efficiency of the electrolysis process is chosen as 70%. Based on Eq. (4), the specific electricity consumption per 1 kg of hydrogen can be determined. To produce 1 kg of green hydrogen, the consumption of electricity is about 47.6 kW h/kg H 2 (for LHV efficiency 70%).
An increase in the hydrogen volume fraction in the fuel increases LHV efficiency and decreases HHV efficiency. When fuel with 100% H 2 is used, HHV and LHV efficiency are 48.7% and 57.5%, respectively. The real efficiency of transforming renewable energy via hydrogen as an energy carrier into electricity in combined cycle power plants is about 38%.
However, if hydrogen is used as a power plant fuel, it is important to determine the energy efficiency. Two types of electrolysis energy efficiency (η e) can be considered: higher heating value (HHV) efficiency and lower heating value (LHV) efficiency.
To produce 1 kg of green hydrogen, the consumption of electricity is about 47.6 kW h/kg H 2 (for LHV efficiency 70%). This value is corresponding to calculation of other authors , . In this case, the HHV efficiency is 82.7%. 3. Hydrogen compression
The electricity consumption for the hydrogen compression E H 2 and the energy efficiency of compression (η c) can be determined from the following equations: (5) E H 2 = ∑ P c o m p, i + Q c o o l C O P ∑ Q O R C η O R C (6) η H H V c = 1 E H 2 m H 2 H H V H 2; η L H V c = 1 E H 2 m H 2 L H V H 2 Table 3.
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